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    Home » Placement Papers » Cognizant Placement Papers » Cognizant Placement Paper 13

    Click here to Download 2007 (Latest) placement papers of this company


    Cognizant Placement Paper 13








    1.LIST, L is defined as : L=( a,b,c ) so that,A(L)=a;

    B(L)=(b,c) [where a,b,c are theitems ]C(L) & D(L) are
    defined as 
    C(L)= * if L=( )=A(L) if L!=( ) & B(L) = (
    )=B(C(4))otherwise 
    D(L)= ** if L=( )=A(L) if L=!( ) &
    ……….=…………=…………based on these ques. 1 to 8 
    eg. L(a,(a,b),(b,c)) given then c( L) =? Or D(
    L)=?2vocabulary: 
    second part is given choose the first part( compound
    word type) 
    (1) -(head)- (a) purpose (b) man (c)obstacle
    (d)(ans:c for blockhead) 
    (2) (dust)- (a) container(b)celestial body
    (c)groom(d)(ans: c for star dust) 
    (3) (stream )-(a) mountain (b) straight (c) (d)
    (ans:a) 
    (4) (crash)- (a) course (b) stock3 anagram 
    first find the anagram of the given word & then 
    choose the meaning of the anagram from the options. 
    1. latter ->rattle 2..spread 3.risque
    4.dangled(ansjogged)…….may be4 series . 
    (1) 2,11,22,121 ,? ans 242 (2)102,211,1020,1210,?7
    another type 
    string S=abc now substrings P=ab Q=ad such that 
    if p->q, then S=adc (according to the
    firstoccurance)based on these type 
    (a) S=abcabc ;P->Q Q->R R->P what would be
    theresulting S ,given P=ab, Q=ba R=bc 
    (b) S=aaabbb; P->Q Q->P R->P (according to the
    firstoccurrence)P=….Q=……R=…… 
    two questions on some figures given (see
    compitionmaster ) 
    type figure1:figure2::figure3:?three number strings
    L1 L2 L3 
    L1 is reduced to L2 with mathematical operation find 
    that operation and reduce L3 to L4 with same
    operation 
    and find the last digit of the string L4eg: 
    L1(6,3,4,4,7,2) reduces to
    L2(20,1,21)L3(50,7,70,40,50,48) 


    *********






    CTS (PSG TECH)

    There are totally 5 sections in the qp and each
    section has 8 
    questions. 

    NO. of questions = 40 
    Time = 60 min 
    Negative marking = 0.25 for each wrong answer 

    SECTION 1(try this at last because it is very tough and time consuming) L1, L2 - lists 
    M(L1,L2) = L1 + L2 
    If , L = (a,b,c) 
    A(L) = a (first term); B(L) = (b,c) (except the first
    term) 

    I] P(L) = L if L=( ), & B(L)=() 
    P(L) = A(B(L)) if L <> ( ), and B(L)<>( ) B(B(L))=( )

    P(L) = M(A(L)), M(A(B(L)), P(B(B(L))) if B(B(L) <>C) 

    II] R(L) = L : B(L)=( ) 
    R(L) = A(L) if L<>() 
    R(L) = M(dont know), R(B(B(L)))if B(B(L)) <>( ) 

    With the above instructions, find the following using
    iterations: 
    1. R(P(L)) where L=(a,b,(a,b),(b,a)) 
    2. R(P(L)) where L=(a,(a),(b,b),b) 

    Example(1)P(L)=P(a,b,(a,b),(b,a)) 
    where A(L)=(a) 
    B(L)=(b,(a,b),(b,a)) 
    B(B(L))=((a,b),(b,a)) 
    So, third condition is applicable 
    So, P(L)=M(a,M(b,P((a,b),(b,a))) find this using the
    same rule and 
    iterate. 



    SECTION 2

    Question and Answers don't know 
    If GODG is a valid work, then the no. of valid words
    in the 
    string (GGODGG, 
    GGOGGD, GGOGDGGG, ....) 
    (* Not aware of correct procedure) 



    SECTION 3

    A 'TARGET' is a number and 'BRICK' has five numbers
    as clue. 
    Use only four 
    numbers (only once each number) from 'BRICK' using
    arithmetic 
    opertions, 

    +,-,*,/,() and attain the 'TARGET' 
    1. TARGET = 114 BRICK = 
    2. TARGET = 19 BRICK = 8,11,5,5,2 
    3. TARGET = 87 BRICK = 
    4. TARGET = 146 BRICK = 
    5. TARGET= 127 BRICK = 

    Ans: for 2 questions 
    19 = (8+11-5+5) 
    so ans = (8,11,5,5) 



    SECTION 4

    There might be question of following kind: 
    1. C_G_I__NT 
    ans. cognizant 
    in answer you have to select the most probable
    meaning of cognizant. i.e. knowledgeable. 
    other ans. are 
    utopia, 
    quixotic, 


    SECTION 5
    1. Head of attack (See "a'') 
    Ans: attribute 

    2. Head of cuticls 
    Ans:cutlass 

    3. Garment leaves with article at end 
    Ans: cloaka 

    4. Good tailors does this 
    Ans: benefit 
    CTS 98 IIT MADRAS


    Analogies

    1. slur : speech 
    ans: smulge : writing (choice is B) 
    7. cpahlet : shoulder 
    ans: ring : finger (choice is C) 
    8. vernanlar : place 
    ans: finger print : identical (choice is B) 

    opposite 
    -------- 
    9.corphlent 
    ans: emaciated (choice is D) 
    10. officious 
    ans: pragmate (choice is D) 
    11. dextrous 
    ans: clumsy (choice is B) 

    12 -14: each sentense is broke to four sections
    a,b,c,d.choose which has 
    mistake mark (e) if you find no mistake. 

    12:a)phylchologists pointout that b)there are human
    processes 
    c)which does not involve d) the use of words 
    (choice is A) 
    13:a)jack ordered for b)two plates of chicken c)and a
    glass d)of water 
    (choice is A) 
    14:a) politics is b) (choice is A) 
    (are) 
    16 - 20: each question of group of questions is based
    on a passage or a set 
    of conditions for each question,select the best
    answer choice given. 

    (i).if it is fobidden by law if the object of
    agreement is the doing of an 
    act, 
    that is forbidden by law the agreement is void. 

    (ii). if it is of the nature that,it would defeat the
    provision of any law 
    is the agreement is void.if the object of agreement
    is such that thing got 
    directly forbidden by law it would defeat the
    provision of statuary law. 

    (iii). if the object of agreement is fraddulent it is
    void. 

    (iv). an object of agreement is void if it involves
    or implies to the 
    personnal property of another. 

    (v). an object of agreement is void where the
    constant regards as ignored. 

    (vi). an object of agreement is void where the
    constant regards is as opposed 

    to public policy. 

    17. A,B,C enter an agreement for the division a many
    them of gains acqest 
    or by be acquit by them by them by the argument is
    void as 
    ans: ---- (choice is D) 

    21-25) An algorithem follws a six step process
    za,zb,zc,zd,ze,zf, it is 
    governed by follwing 
    (i) zd should follw ze 
    (ii) the first may be za,zd or zf 
    (iii) zb and zc have to be performed after zd 
    (iv) zc must be immediately after zb 
    21) ans:- D 


    22) if za the first set zd must be 
    a) 3rd b)5th c)2nd d)4th ans:- A or D (probably a) 

    23) zf can be 3rd or 5th------any of the six, first,
    second or forth only, 
    any of first four only 
    none these 
    ans:- B 
    24) if zb must follw za then a)za can only 3rd or
    fourth 
    b) first or second c) can not be third d) fouth or
    fifth e)none 
    ans:- A 
    25) ze is third term the no of diff operations
    possible is 
    ans:- D (dabad) 

    26-31) ravi plans six sep-- x,y,z,w,u,v in rows no 1
    to 6 ,according to the 
    follwing conditions 
    he must plant x before y and u 
    he must plant y " w 
    the 3rd has to be z 

    26) which could be in order 
    a) xuywzv b) xvzyuw c)zuyxwv d)zvxuwy e) wyzuvx 
    ans:- B 

    27) which is true 
    a) z before v b) z before x c) w before u d) y before

    e) x before w 
    ans:- D 

    28) if he plans v first which is second 
    x,y,z,w,u 
    so ans is 'x'. 
    choice is A. 
    29) which is true 
    a) x,3 b)y,6 c)z,1 d)w,2 e)u,6 
    ans:- E 

    30) if he plans b 6th which would be first and second

    a) x and w b) x and y c)y and x d)w and z e) w and u 
    ans:- B 

    31) if he plans w before u and after v he should plan
    w at 
    a) first b)second c)fourth d)fifth e)sixth 
    ans:- D 
    32)thursday 
    33)a&d 
    34)south hit 
    35) 

    36)at a certain moment a watch showes 2 min lag
    althogh it is fast.if it 
    showed a 3 min lag at that moment ,but gain 1/2 min
    more a day than it does. 

    it would show the true time one day sooner than it
    usually does .how many 
    mins does the watch gain per day. 
    a).2 b).5 c).6 d).4 e).75 
    ans : e 
    ---->(discount problem) 20%->15%then->32% (ans:32%) 
    37)in 400m race a gives b a start of 7 sec & beats by
    24m.in another race 

    a beats by 10 sec.the speeds are 
    a)8,7 b)7,6 c)10,8 d)6,8 e)12,10 
    ans:c(10,8) 
    38)3x+4y=10 
    x cube+y cube=6 minimum value of 3x+11y=? 
    ans=? 
    39)0.75 
    40)- 
    41)sink---7.7kms---> 
    fills 2 1/4 t is 5.5 min. 92 tonnes enough.. sink
    throws out 18 tonnes/hr. 
    avg. speed to 
    a)1.86 b)8.57 c)9.4 d)11.3 e)10.7 

    42) . ______ 
    / \ 2 2 cms 
    /_a_\ ______ 
    / \ 3 2 cms area of the d=50 cm square 
    /___b___\ ______ what is the area of the b=? 
    / \ 4 2 cms 
    /_____c_____\ ______ 
    / \ 5 2 cms ans=(10.7) 
    /_______d________\ ______ 
    43)600 tennis players 
    4% ->wrist band on one wrist 
    of remain 96%->25%->on both hands 
    remain no of ---(ans:312) 
    44)312(doubt) or 432 
    45)in how many ways 5e,6s,3f be arranged if books of
    each language are to be 
    kept together 
    17,64800,90,58400,3110400 
    ans:e(3!*5!*6!*3!=3110400) 
    46)--- 
    47)three types of the a,b,c costs Rs.
    95/kg,100/kg&70/kg .how many kg of 
    each be blended to produce 100 kg of mixture worth
    Rs.90/kg,gives that 
    the quntities of b&c are equal 
    a)70,15,15 b)50,25,25 c)60,20,20 d)40,30,30 
    ans:b 
    48)water milk problem 
    49)x+y+z=w 


    q)two distinct no's are taken from 1,2,3,4......28 
    a)probably that the no is 6 -->1/14 
    b)probably that it exceeds 14 -->1/28 
    c)both exceed 5 is 3/28 
    d)less than 13->25/28 (24/28) 
    e)noneCTS '99 
    Pondicherry 

    SECTION I - 8 questions Series.

    1. Interchange of letters in a word and the adjacent
    letters are also to 
    be changed. given letters series like [also few
    condotions] 
    AAABBB= 
    ABABAB= 
    LET QUESTION IS ABBAAB 
    If we apply 25 on this it means we have to
    interchange the letters 
    at positions 2 and 5, and we have to change the
    adjacent letters 2 and 5 
    from A to B and B to A. 
    That is q's A B B A A B 
    after Step 1 i.e interchange 2 and 5. 

    now change adjacent elements of 2 and 5...finally
    answer becomes 
    Ans: B A A B B A 

    //Hint: As per question papers 5 questions above like
    but numbers 
    change. 

    REMAINING 3 QUESTIONS: 
    6. To get AAABBD from BBBAAA what ot apply:- 
    a) 25 b) 34 c)25 & 34 d) none 


    SECTION II
    1. Given the function f(n a b c ) = ac if n=1 
    f(n a b c) = f( n-1 a b c) + f( 1 a b c) + f( n-1 b a
    c ) 
    if n > 1 
    f( 2) = ? 
    Ans: f( 2 a c b ) = ab + ac + bc. 

    2. similar question in functions. 
    3. [ based on function in 1.] f( 4 a b c ) the number
    of terms is...? 
    Ans: f( 4 a b c ) = f( 3 a c b ) + f( 1 a b c ) + f(
    3 b a c ) etc. 
    = 5ab + 5ac + 5bc. 
    4. f( 5 a b c ) = ? 

    SECTION III
    Permutations and Combinations 8 questions


    1. r = number of flags; 
    n = number of poles; 
    Any number of flags can be accommodated on any single
    pole. 

    i) r=5,n=5 The no. of ways the flags can be arranged

    ii) to iv) are based on this. 

    6. r= 5 n = 3 . If first pole has 2 flags ,third pole
    has 1 flag 
    how many ways the remaining can be arranged? 
    7.& 8. same as above. 

    SECTION IV

    Question consising of figures consist of 4 small

    squares and every square
    having an arrow pointing in one Direction. 

    GRE test of reasoning. 
    hint: What is the next sequence if we tilt the figure
    by 90 degrees like 
    that( clockwise and mirror images ? ). 

    SECTION V 
    In this section first part of compound word is given.
    Select meaning of 
    the second part from the choice given: 
    1. Swan 
    2. Swans 
    3. Fool 
    4. Fools 
    5. Stare 
    6. Lady 
    For all above 4 choices are given..... 
    Eg. Swan 
    a) category b) music c) --- d) none 
    Ans: Swansong is compound word. But song is not given
    as option. so 
    b) music is answer. 




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