Section 1 Try this at last because it is very tough and time consuming.L1, L2 - lists

M(L1,L2) = L1 + L2

If , L = (a,b,c)

A(L) = a (first term); B(L) = (b,c) (except the first term)

I] P(L) = L if L=( ), & B(L)=()

P(L) = A(B(L)) if L < ( ), and B(L)<( ) B(B(L))=( )

P(L) = M(A(L)), M(A(B(L)), P(B(B(L))) if B(B(L) <C)

II] R(L) = L : B(L)=( )

R(L) = A(L) if L<()

R(L) = M(dont know), R(B(B(L)))if B(B(L)) <( )

With the above instructions, find the following using iterations:1. R(P(L)) where L=(a,b,(a,b),(b,a))

2. R(P(L)) where L=(a,(a),(b,b),b)

Example:

(1)P(L)=P(a,b,(a,b),(b,a))

where A(L)=(a)

B(L)=(b,(a,b),(b,a))

B(B(L))=((a,b),(b,a))

So, third condition is applicable

So, P(L)=M(a,M(b,P((a,b),(b,a))) find this using the same rule and iterate.

Section 2 If GODG is a valid word, then the no. of valid words in the string (GGODGG, GGOGGD, GGOGDGGG, ....)

Section 3 A 'TARGET' is a number and 'BRICK' has five numbers as clue. Use only four numbers (only once each number) from 'BRICK' using arithmetic opertions, +,-,*,/,() and attain the 'TARGET'

1. TARGET = 114 BRICK =

2. TARGET = 19 BRICK = 8,11,5,5,2

3. TARGET = 87 BRICK =

4. TARGET = 146 BRICK =

5. TARGET= 127 BRICK =

Ans: For Question number 2,

19 = (8+11-5+5)

so ans = (8,11,5,5)Section 4 Attend this section first.

Refer chapter - 17 from 'A MODERN APPROACH TO VERBAL, NON VERBAL REASONING'by R. S. Aggarwal. Page: 416 to 420.

There might be questions of following kind:

1. C_G_I__NT

Ans: cognizant.

in answer you have to select the most probable meaning of cognizant. i.e. knowledgeable.

other ans. are utopia, quixotic etc.

Section 5

1. Head of attack (See "a'')

Ans: attribute

2. Head of cuticls

Ans: cutlass

3. Garment leaves with article at end

Ans: cloaka

4. Good tailors does this

Ans: benefit