Section 1 Try this at last because it is very tough and time consuming.
L1, L2 - lists
M(L1,L2) = L1 + L2
If , L = (a,b,c)
A(L) = a (first term); B(L) = (b,c) (except the first term)
I] P(L) = L if L=( ), & B(L)=()
P(L) = A(B(L)) if L < ( ), and B(L)<( ) B(B(L))=( )
P(L) = M(A(L)), M(A(B(L)), P(B(B(L))) if B(B(L) <C)
II] R(L) = L : B(L)=( )
R(L) = A(L) if L<()
R(L) = M(dont know), R(B(B(L)))if B(B(L)) <( )With the above instructions, find the following using iterations:
1. R(P(L)) where L=(a,b,(a,b),(b,a))
2. R(P(L)) where L=(a,(a),(b,b),b)
So, third condition is applicable
So, P(L)=M(a,M(b,P((a,b),(b,a))) find this using the same rule and iterate.Section 2
If GODG is a valid word, then the no. of valid words in the string (GGODGG, GGOGGD, GGOGDGGG, ....)Section 3
A 'TARGET' is a number and 'BRICK' has five numbers as clue. Use only four numbers (only once each number) from 'BRICK' using arithmetic opertions, +,-,*,/,() and attain the 'TARGET'
1. TARGET = 114 BRICK =
2. TARGET = 19 BRICK = 8,11,5,5,2
3. TARGET = 87 BRICK =
4. TARGET = 146 BRICK =
5. TARGET= 127 BRICK =Ans: For Question number 2,
19 = (8+11-5+5)
so ans = (8,11,5,5)Section 4
Attend this section first.
Refer chapter - 17 from 'A MODERN APPROACH TO VERBAL, NON VERBAL REASONING'by R. S. Aggarwal. Page: 416 to 420.
There might be questions of following kind:
in answer you have to select the most probable meaning of cognizant. i.e. knowledgeable.
other ans. are utopia, quixotic etc.
1. Head of attack (See "a'')
2. Head of cuticls
3. Garment leaves with article at end
4. Good tailors does this