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Home » Placement Papers » i2 Placement Papers »i2 Placement Paper 1

# i2 Placement Paper 1

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i2 Technologies

Q1.Convert 0.9375 to binary
a) 0.0111
b) 0.1011
c) 0.1111
d) none
Ans. (c)

Q2.( 1a00 * 10b )/ 1010 = 100
a) a=0, b=0
b)a=0, b=1
c) none
Ans. (b)

Q3. In 32 bit memory machine 24 bits for mantissa and 8 bits for exponent. To increase the range of floating point.
a) more than 32 bit is to be there.
b) increase 1 bit for mantissa and decrease 1 bit for exponent
c) increase 1 bit for exponent and decrease one bit for mantissa

Q4.In C,  "X ? Y : Z "  is equal to
a) if (X==0) Y ;else Z
b) if (X!=0) Y ;else Z
c) if (X==0) Y ; Z
Ans. (b)

Q5. From the following program
foo()
int foo(int a, int b)
{
if (a&b) return 1;
return 0;
}

a) if either a or b are zero returns always 0
b) if both a & b are non zero returns always 1
c) if both a and b are negative returns 0

Q6. The  following function gives some error. What changes have to be made
void ( int a,int b)
{
int t; t=a; a=b; b=t;
}
a) define void as int and write return t
b) change everywhere a to *a and b to *b

Q7. Which of the following is incorrect
a) if a and b are defined as int arrays then (a==b) can never be true
b) parameters are passed to functions only by values
c) defining functions in nested loops

Q8.  include<stdio.h>
void swap(int*,int*);
main()
{
int arr[8]={36,8,97,0,161,164,3,9}
for (int i=0; i<7; i++)
{
for (int j=i+1; j<8;j++)
if(arr[i]<arr[j]) swap(&arr[i],&arr[j]);
}
}
void swap(int*x,int*y)
{
int temp; static int cnt=0;
temp= *x;
*x=*y;
*y=temp;
cnt++;
}
What is cnt equal to

a) 7
b) 15
c) 1
d) none of these

Q9.      int main()
{
FILE *fp;
fp=fopen("test.dat","w");
fprintf(fp,'hello\n");
fclose(fp);
fp=fopen ("test.dat","w");
fprintf (fp, "world");
fclose(fp);
return 0;
}

If text.dat file is already present after compiling and execution how many bytes does the file occupy ?

a) 0 bytes
b) 5 bytes
c) 11 bytes
d) data is insufficient

Q10.    f1(int*x,intflag)
int *y;
*y=*x+3;
switch(flag)
{
case 0:
*x=*y+1;
break;
case 1:
*x=*y;
break;
case 2:
*x=*y-1;
break;
}
return(*y)

main()
{
*x=5;
i=f1(x,0); j=f1(x,1);
printf("%d %d %d ",i,j,*x);
}

What is the output?

a) 8 8 8
b) 5 8 8
c) 8 5 8
d) none of these

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